Optimal. Leaf size=62 \[ -\frac{2 e^{2 i a} x^3}{x^2+e^{2 i a}}+6 e^{2 i a} x-6 e^{3 i a} \tan ^{-1}\left (e^{-i a} x\right )-\frac{x^3}{3} \]
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Rubi [F] time = 0.0498105, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int x^2 \tan ^2(a+i \log (x)) \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int x^2 \tan ^2(a+i \log (x)) \, dx &=\int x^2 \tan ^2(a+i \log (x)) \, dx\\ \end{align*}
Mathematica [A] time = 0.119622, size = 100, normalized size = 1.61 \[ \frac{2 x (\cos (3 a)+i \sin (3 a))}{\left (x^2+1\right ) \cos (a)-i \left (x^2-1\right ) \sin (a)}+4 i x \sin (2 a)+4 x \cos (2 a)-6 \cos (3 a) \tan ^{-1}(x (\cos (a)-i \sin (a)))-6 i \sin (3 a) \tan ^{-1}(x (\cos (a)-i \sin (a)))-\frac{x^3}{3} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.078, size = 0, normalized size = 0. \begin{align*} \int{x}^{2} \left ( \tan \left ( a+i\ln \left ( x \right ) \right ) \right ) ^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.64488, size = 363, normalized size = 5.85 \begin{align*} -\frac{2 \, x^{5} - x^{3}{\left (22 \, \cos \left (2 \, a\right ) + 22 i \, \sin \left (2 \, a\right )\right )} - x{\left (36 \, \cos \left (4 \, a\right ) + 36 i \, \sin \left (4 \, a\right )\right )} -{\left (x^{2}{\left (18 \, \cos \left (3 \, a\right ) + 18 i \, \sin \left (3 \, a\right )\right )} +{\left (18 \, \cos \left (2 \, a\right ) + 18 i \, \sin \left (2 \, a\right )\right )} \cos \left (3 \, a\right ) - 18 \,{\left (-i \, \cos \left (2 \, a\right ) + \sin \left (2 \, a\right )\right )} \sin \left (3 \, a\right )\right )} \arctan \left (\frac{2 \, x \cos \left (a\right )}{x^{2} + \cos \left (a\right )^{2} - 2 \, x \sin \left (a\right ) + \sin \left (a\right )^{2}}, \frac{x^{2} - \cos \left (a\right )^{2} - \sin \left (a\right )^{2}}{x^{2} + \cos \left (a\right )^{2} - 2 \, x \sin \left (a\right ) + \sin \left (a\right )^{2}}\right ) +{\left (9 \, x^{2}{\left (-i \, \cos \left (3 \, a\right ) + \sin \left (3 \, a\right )\right )} + 9 \,{\left (-i \, \cos \left (2 \, a\right ) + \sin \left (2 \, a\right )\right )} \cos \left (3 \, a\right ) +{\left (9 \, \cos \left (2 \, a\right ) + 9 i \, \sin \left (2 \, a\right )\right )} \sin \left (3 \, a\right )\right )} \log \left (\frac{x^{2} + \cos \left (a\right )^{2} + 2 \, x \sin \left (a\right ) + \sin \left (a\right )^{2}}{x^{2} + \cos \left (a\right )^{2} - 2 \, x \sin \left (a\right ) + \sin \left (a\right )^{2}}\right )}{6 \, x^{2} + 6 \, \cos \left (2 \, a\right ) + 6 i \, \sin \left (2 \, a\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{2 \, x^{3} +{\left (e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 1\right )}{\rm integral}\left (-\frac{x^{2} e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 7 \, x^{2}}{e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 1}, x\right )}{e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 1} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.655233, size = 66, normalized size = 1.06 \begin{align*} - \frac{x^{3}}{3} + 4 x e^{2 i a} + \frac{2 x e^{4 i a}}{x^{2} + e^{2 i a}} - 3 \left (- i \log{\left (x - i e^{i a} \right )} + i \log{\left (x + i e^{i a} \right )}\right ) e^{3 i a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.24315, size = 190, normalized size = 3.06 \begin{align*} -\frac{x^{5}}{3 \,{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )}} + \frac{10 \, x^{3} e^{\left (2 i \, a\right )}}{3 \,{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )}} - 6 \, \arctan \left (x e^{\left (-i \, a\right )}\right ) e^{\left (3 i \, a\right )} + \frac{35 \, x e^{\left (4 i \, a\right )}}{3 \,{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )}} + \frac{2 \, x e^{\left (4 i \, a\right )}}{x^{2} + e^{\left (2 i \, a\right )}} + \frac{8 \, e^{\left (6 i \, a\right )}}{{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )} x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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